Plus One - Leetcode Problem solved by java

 66. You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0's.

Increment the large integer by one and return the resulting array of digits.

Example 1:

Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].

Example 2:

Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].

Example 3:

Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].

 

Constraints:

  • 1 <= digits.length <= 100
  • 0 <= digits[i] <= 9
  • digits does not contain any leading 0's.


First, try Yourself. By seeing any youtube video.

Code:
class Solution {
    public int[] plusOne(int[] digits) {
        int n = digits.length;
        for(int i=n-1; i>=0; i--){
            if(digits[i]<9){
                digits[i]++;
                return digits;
            }
            digits[i]=0;
        }
        int[] new_digits = new int[n+1];
        new_digits[0] = 1;
        return new_digits;
     
        
    }
}

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